Quantum Mechanics Practice Test - Answer Key
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- Would light of wavelength (650 nm) be able to excite an electron in Be3+ from n=2 to n=6?
No.
- Determine the number of orbitals that can have the following designation
- n = 4
16
- n = 3 ml = 2
1
- 2p
3
- How many electrons can have the following designation
- 3d ml ms = + ½
1 electron
- n = 6 ml = 2
8 electrons
- Determine if the energy is absorbed or emitted when an electron transitions from the n=7 to the n=2 energy level of C5+ and the wavelength of the photon associated with the transition.
Energy is emitted and has a wavelength of 11.0 nm
- It takes 208.4 kJ of energy to remove 1 mole of electrons from the atoms on the surface of rubidium metal. If rubidium metal is irradiated with 254-nm light, what is the maximum velocity of the released electron?
v = 976114 m/s
- Consider and atom traveling at 2.78 x 108 m/s. The De Broglie wavelength is found to be 1.797 x 10-5 pm. Which element is this?
Bromine
- What is the electron configuration for
- Fe2+: [Ar]3d6
- As2-: [Ar]4s23d104p5
- Given:
The figure below represents part of the emission spectrum for a one-electron ion in the gas phase. All the lines result from the electronic transition to the n = 3 state.
- What electronic transition corresponds to lines A and B?
A: 6 à 3
- If the wavelength of line B is 142.5 nm, calculate the wavelength of line A.
λ = 121.7 nm