Entropy Worksheet - Answer Key
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- What is a spontaneous process?
A process that requires no external assistance to occur.
- True or False: Spontaneous reactions are fast.
False. Diamond → Graphite is spontaneous but it happens very slowly. Spontaneity is no indication of speed.
- What is entropy?
Scientists wondered why some reactions were spontaneous. Entropy is what they decided to call the reason for spontaneity. Ultimately entropy is a measure of disorder related to positional probability. How many ways something can placed in space.
- Why do things tend toward disorder?
- There are more paths to disorder.
- Less energy required to be disordered.
- What state of matter has the highest entropy?
The gaseous phase.
- Determine the sign of ΔS:
- CaCO3(s)→CaO(s) + CO2(g) +ΔS
- N2(g) + 3H2(g)→ 2NH3(g) -ΔS
- What is an arrangement versus a microstate?
An arrangement represents the number of ways a system can be set so that one arrangement is distinct from another. A microstate, on the other hand, represents the number of ways that a particular arrangement can be reorganized so that it has the same overall “big picture” (macroscopic) appearance.
- There are multiple equations for entropy. The first relates it to the number of microstates a system has:
S = kb ln Ω
- Why is this not a very useful equation?
Actual gas samples (with multiple molecules of gas) have far too many microstates to account for.
- What would the change in entropy be for the following system change?
ΔS = - kbln3
- What are the 3 additional equations for entropy, and in which case do you use each?
- Constant Temperature
ΔST = nR ln (V2/V1) = qreversible
- Constant Pressure
ΔSP = nR ln (T2/T1)
- Constant Volume
ΔSV = nR ln (T2/T1)
- One mole of an ideal gas with a volume of 1.0L and a pressure of 5.0 atm is allowed to expand isothermally into an evacuated bulb to give a total volume of 2.0L. Calculate w and q.
q = 0
- The molar heat capacities for CO2 at 298.0K are
Cv=28.95 J/molK
Cp=37.27 J/molK
The molar entropy of CO2 gas at 298.0 K and 1.000 atm is 213.64 J/mol K
- Calculate the energy required to change the temperature of 1.000 mol of CO2 from 298.0K to 350.0K, both at constant volume and at constant pressure.
qV = 1505.4 J
- Calculate the molar entropy of CO2 gas at 350.0K and 1.000 atm.
S = 219.6 J/K
- Calculate the molar entropy of CO2 gas at 350.K and 1.174 atm.
S = 218.3 J/K
- Calculate the entropy change for a process in which 3.00 mol of liquid water at 0°C is combined with 1.00 mol of water at 100.0°C in a perfectly insulated container. (Assume the molar heat capacity of water is constant at 75.3J/Kmol)
ΔS = 2.9 J/K
- When changes in state happen under isobaric conditions. What relationship is established?
Because these processes are assumed to be occurring at constant pressure, ∆H = q.
- What are the changes of state for each of the following?
- Fusion is when a solid → liquid
- Vaporization is when a liquid → gas.
- Sublimation is when a solid → gas
- Condensation is when a gas → liquid
- Freezing is when a liquid → solid
- Deposition is when a gas → solid
- The equation to find the change in entropy during a state change are:
- ΔSfusion = ΔHfusion .
- ΔSvaporization = ΔHvaporization
- ΔSsublimation = ΔHsublimation
- A sample of ice weighing 1.00 mol, initially at a temperature of -30.0°C, is heated to 140.0°C at a constant pressure of 1.00 atm. Calculate q, w, ΔH, ΔE, and ΔS. For the process. The molar heat capacities (Cp) for solid, liquid, and gaseous water are 37.5 J/mol K, 75.3 J/mol K, and 36.4 J/mol K respectively. The enthalpies of fusion and vaporization are 6.01 kJ/mol and 40.7 kJ/mol, respectively. Assume ideal gas behavior.
q = ∆H = 56.8 kJ
- For mercury, the enthalpy of vaporization is 58.51 kJ/mol and the entropy of vaporization is 92.92J/molK. What is the normal boiling point?
Tboiling point= 629 K
- What do the following signs/values of ΔSuniv indicate?
- + : spontaneous
- – : non-spontaneous
- 0 : at equilibrium
- What sign of ΔSsurroundings would be assigned for
- Exothermic: + ∆Ssurroundings
- Endothermic: - ∆Ssurroundings