Rate Laws Worksheet - Answer Key
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- Kinetics is the study of the rates of reaction.
- What is a Rate Law?
The equation that defines the rate of a particular reaction at a particular temperature.
- How is a rate law determined?
It must be experimentally determined.
- What are the two types of rate law and what does each compare?
- Differential Rate Law
This rate compares how the rate of the reaction changes as the concentrations change.
- Integrated Rate Law
This rate compares how the concentrations change with time.
- The general appearance of a differential rate law is:
Rate = k [Reactant]n
- Where k represents the rate constant.
- What are the units for k?
k units = . L n-1 .
moln-1 s
- Where n represents the order of reaction.
- If n=1 this is said to be a first order reaction.
- If n=2 this is said to be a second order reaction.
- If n=0 this is said to be a zero order reaction.
- If there is more than one reactant in a rate law you must add their n values to determine the overall order of the reaction.
- For a zero order reaction
- What does zero order tell us with respect to concentration & rate?
When a reaction is zero order with respect to some species a change in its concentration has no effect on the rate of reaction (the rate remains unchanged).
- Differential Rate Law
Rate = k
- Integrated Rate Law
[A] = -kt + [A]o
- How can we utilize this information?
An important point about the format of the equation is that a reaction is zero order if a graph of [A] vs. t yields a straight line.
- Half Life Equation
t1/2 = [A]o
2k
- For a first order reaction
- What does first order tell us with respect to concentration & rate?
In a first order case, the rate will change by the same factor that the concentration of the reactant changes.
- Differential Rate Law
The general appearance of the first order rate law looks like:
Rate = k [A]
- Integrated Rate Law
ln [A] = -kt + ln[A]o
- What format is this equation written in? How can we utilize this information?
The important thing about the format of the equation is that a reaction is first order if a graph of ln[A] vs. t yields a straight line.
- Half Life Equation
t1/2 = 0.693
k
- For a second order reaction
- What does second order tell us with respect to concentration & rate?
In the second order case the change in the rate of reaction is equal to the factor of concentration change squared.
- Differential Rate Law
The general appearance of the second order rate law looks like:
Rate = k [A]2
- Integrated Rate Law
1 . = kt + 1 .
[A] [A]o
- What format is this equation written in? How can we utilize this information?
The important thing about the format of the equation is that you can tell if a reaction is second order if a graph of 1/[A] versus t yields a straight line.
- Half Life Equation
t1/2 = 1 .
k[A]o
- Determine the differential rate law and rate constant for
2NO(g) + Cl2(g)→ 2NOCl(g)
given:
[NO]o [Cl2]o Initial Rate
0.10 M 0.10 M 0.18 M/min
0.10 M 0.20 M 0.36 M/min
0.20 M 0.20 M 1.45 M/min
Rate = k [NO]2[Cl2]
k = 180 M-2 min-1
- Determine the rate law for
given:
1.98 x 10-9 1.66 x 10-9 2.99 x 10-10
4.15 x 10-9 4.15 x 10-9 5.20 x 10-10
Rate = k [NO]2[O2]
- A certain reaction has the following general form
aA→bB
At a particular temperature and [A]0=2.80 x 10-3 M concentration versus time data were collected and a plot of 1/[A] versus time resulted in a straight line with a slope value of +3.60 x 10—2 L/mol*min
- Determine the differential and integrated rate laws and the value of the rate constant.
Differential Rate Law:
Rate = k[A]2
Integrated Rate Law:
1 . = kt + 1 .
[A] [A]o
k = 3.60 x 10-2 M-1 min-1
- Calculate the half-life for this reaction.
t1/2 = 9921 min
- How much time is required for the concentration of A to decrease to 2.50 x 10-3M?
t = 1109 minutes
- The decomposition of hydrogen peroxide was studied and the following data was obtained:
0 1
120 0.91
300 0.78
600 0.59
1200 0.37
1800 0.22
2400 0.13
3000 0.082
3600 0.05
- Determine the integrated rate law, the differential rate law, and the value of the rate constant.
Differential Rate Law: Rate = k[H2O2]
Integrated Rate Law: ln[H2O2] = -kt + ln[H2O2]o
k = 0.00083
- Calculate the [H2O2] at 4000. s after the start of the reaction.
0.0362 M
- A first order reaction is 75.0% complete in 320. s.
- What are the first and second half-lives for this reaction?
160s per half life
- How long does it take for this reaction to be 90.0% complete?
t = 531 s